First overall pick Zion Williamson signs with Jordan; Joins Celtics' Kemba Walker and Jayson Tatum

Zion Williamson announces signed deal with Jordan Brand. Graphic provided via Nike, INC

Yesterday, it was announced that 2019 first overall draft pick Zion Williamson of Duke University had agreed to a shoe deal with the Jordan Brand.
Forbes writer Adam Zagoria reported from an "industry source" that the deal was worth $75 million over the span of 7 years. This would be the largest rookie shoe deal for a player since Nike signed a young LeBron James in the summer of 2003 for $90 million. Zion announced the news on his Instagram with a short video graphic Tuesday afternoon.

A post shared by Zion Williamson (@zionwilliamson) on

Clearly, the young superstar must be thrilled about the opportunity. When asked what it meant to him Zion replied saying:
"I feel incredibly blessed to be apart of the Jordan Brand family. Since I was a kid, I dreamed of making it to the league and having the type of impact on the game Michael Jordan had and continues to have today. He was one of those special athletes I looked up to, and I really can't express how happy and excited I am for this journey."
It's hard to not believe the sincerity in Zion's words, especially when you take into account that sources have reported Williamson turned down more lucrative offers from other brands in the industry.

Clearly, the feelings of excitement must be mutual as the Jordan Brand quickly posted digital billboards of Zion and the announcement in New Orleans, New York City, and Los Angeles.

Joining the team, Williamson will be represented with the likes of NBA superstars such as Russell Westbrook, Blake Griffin, and the Celtics duo of Kemba Walker and Jayson Tatum. You can catch Zion Williamson in a pair of Jordans when he starts the 2020 NBA season as a member of the New Orleans Pelicans.
You can follow Thomas Desmond on Twitter at @td_654.